6sin(2x)+5cos^2(x)=0

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Solution for 6sin(2x)+5cos^2(x)=0 equation:


Simplifying
6sin(2x) + 5cos2(x) = 0

Remove parenthesis around (2x)
6ins * 2x + 5cos2(x) = 0

Reorder the terms for easier multiplication:
6 * 2ins * x + 5cos2(x) = 0

Multiply 6 * 2
12ins * x + 5cos2(x) = 0

Multiply ins * x
12insx + 5cos2(x) = 0

Multiply cos2 * x
12insx + 5cos2x = 0

Reorder the terms:
5cos2x + 12insx = 0

Solving
5cos2x + 12insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12insx' to each side of the equation.
5cos2x + 12insx + -12insx = 0 + -12insx

Combine like terms: 12insx + -12insx = 0
5cos2x + 0 = 0 + -12insx
5cos2x = 0 + -12insx
Remove the zero:
5cos2x = -12insx

Divide each side by '5os2x'.
c = -2.4ino-1s-1

Simplifying
c = -2.4ino-1s-1

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